1880 United States presidential election in Delaware

1880 United States presidential election in Delaware

← 1876 November 2, 1880 1884 →
 
Nominee Winfield S. Hancock James A. Garfield
Party Democratic Republican
Home state Pennsylvania Ohio
Running mate William H. English Chester A. Arthur
Electoral vote 3 0
Popular vote 15,181 14,148
Percentage 51.53% 48.03%

County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James Garfield
Republican

The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Delaware was won by General Winfield Scott Hancock (DPennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.[1]

As of 2023, this is the most recent time that a Republican won the presidency without carrying Sussex County.

  1. ^ a b "1880 Presidential Election Results Delaware".

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